v IN = 0 v OUT = V DD r DSN r PDN

Transkript

1 MOS Inverer = 0 = = = 0 r SDP r SDP r DSN r DSN

2 MOS Inverer r SDP = 0 = Q P : Triode small v SD Q N : uoff = r SDP r DSN

3 MOS Inverer r SDP = 0 = Q P : Triode small v SD Q N : uoff = r SDP

4 MOS Inverer r SDP = = 0 Q P : uoff Q N : Triode small v DS = r DSN r DSN

5 MOS Inverer = = 0 Q P : uoff Q N : Triode small v DS = r DSN r DSN

6 MOS Inverer = = 0 Q P : uoff Q N : Triode small v DS = r DSN = 0 = Q P : Triode small v SD Q N : uoff = r SDP

7

8

9 MOS Inverer

10 MOS Inverer

11 MOS Inverer

12 MOS Inverer

13 MOS Inverer = = 0 Q P : uoff Q N : Triode small v DS = r DSN = 0 = Q P : Triode small v SD Q N : uoff = r SDP

14 MOS Inverer = 0 = Q P : Triode small v SD Q N : uoff = r SDP = = 0 Q P : uoff Q N : Triode small v DS = r DSN

15 MOS Inverer = 0 = = = 0

16 (), () =? =0 ()=? =0 + ()=? =0 -

17 (), () =? =0 (0)= =0 + ()=? =0 -

18 (), () ()/ = () =0 () = A1 exp(-/( )) + A 2 (0)=, ( )=0 () = exp(-/( )) (0)= =0 + () =0 -

19 (), () =0 ()=, < 0 () = exp(-/( )) > 0 (0) =0 + () =0 -

20 (), () () = exp(-/( )) i r = / = ( / ) exp(-/( )) P PDN = 2 / P PDN = (2 / ) exp(-2/( )) (0) =0 + () =0 -

21 (), () =0 =0 - ()=0 (0)=? =0 +

22 (), () =0 () = 0, < 0 () = exp(-/( )) > 0 =0 - ()=0 () =0 +

23 (), () =0 () = 0, < 0 () = exp(-/( )) > 0 =0 - ()=0 () =0 +

24 (), () () = exp(-/( )) i r = ( )/ = ( / ) exp(-/( )) P PUN = (2 / ) exp(-2/( )) P SUPPLY = (2 / ) exp(-/( )) =0 - ()=0 () =0 +

25 (), () ()=? ()=?

26 (), () i (), i SUPPLY () P SUPPLY, P PUN,PDN

27 (), () P SUPPLY = (2 / ) exp(-/( )) P AVG = (1/T) T (2 / ) exp(-/( ) d P AVG = - (1/T) (2 / ) exp(-/( ) 0 o T P AVG = (1/T) (2 ) if << T P SUPPLY, P PUN,PDN P AVG = f 2

28 (), () τ PHL = 50 on op plo τ PLH = 50 on boom plo τ THL = on op plo τ TLH = on boom plo

29 (), () =0 ( 50 ) = exp(- 50 /( )) = /2-50 /( ) = ln(1/2) 50 = ln(2) - 10 /( ) = ln(1/10) 10 = ln(10) - 90 /( ) = ln(9/10) 90 = ln(10/9)

30 (), () =0 τ PHL = 50 = ln(2) τ THL = = ln(10) ln(10/9) τ THL = (ln(10) ln(10/9)) = ln(10 9/10) τ PHL = ln(2) τ THL = ln(9)

31 (), () τ PHL,τ PLH =,PUN ln(2) τ THL,τ TLH =,PUN ln(9) This is for he simple model of a resisior and capacior.

32 (), () =0 5 4 v IN v O U T () = exp(-/( )) k n = 130 ma/v V n = 1.62 V = 5 V = 200 nf = r DS = 1/(.130*(5-1.62)) = 2.27 Ω = 454 nsec () = 5 exp(-/(454x10-9 )) v ime (usec)

33 5 4 3 k n = 130 ma/v V n = 1.62 V = 5 V = 200 nf v ime (usec)

34 (), () P AVG = f 2 τ PHL,τ PLH =,PUN ln(2) τ THL,τ TLH =,PUN ln(9) For his model he minimum clock period is proporional o τ THL or τ THL. f max ~ 1/τ T ~ 1/(,PUN ) r SD,DS = 1/(k (W/L)( -V ))

35 (), () P AVG = N f 2 f max ~ (2/) k (W/L) ( -V ) A = N W L Performance (f max ) vs. Power Dissipaion (P D ) vs. Area/Number (A,N) (assume always operaing a f max ) 1. Increase (Power vs f max ) f max f max goes up by -V Power goes up by ( -V ) 2 2. Increase W/L (f max vs A) f max goes up by W Power goes up by W Uses more area on he I 3. Find a beer process ha has Larger k P D Smaller, bu k =µ ox, so maybe higher mobiliy. Smaller V A

36 MOS Inverer

37 (), () =? =0 For his model, he oupu volage would be a 2 nd order differenial equaion. a. overdamped. b. underdamped (ringing) c. criically ()=? =0 + ()=? =0 -